Question

2x^2-x-3=3
Solve for X

Answer 1

i did (2x-3)(x+1)=0

Answer 2

I gave you medal bcz u r right. :D

Answer 3

thanks, but how do I solve from there?
is one answer 1.5 and the other -1?

Answer 4

RIght.

Answer 5

2x - 3 = 0 & (x + 1) = 0

Answer 6

hey is this the question
\[2x^2-x-3=3\]

Answer 7

no

Answer 8

it equals 0

Answer 9

ok \[2x^2-x-3=0\]
\[2x^2-3x+2x-3=0\]
\[x(2x-3)+1(2x-3)=0\]
\[(x+1)(2x-3)=0\]
either x+1 = 0 or 2x-3 = 0
x=-1 or x=-3/2