Question

log(b)√3x=_____
write as a sum of multiples of logarithms.

Answer 1

now go the other way
\[\log(\sqrt{3x})=\frac{1}{2}\log(3x)=\frac{1}{2}(\log(3)+\log(x))\]

Answer 2

\[log_b\sqrt{3x}=\frac{1}{2}log_b(3x)\]
\[\frac{1}{2}log_b(3x)=\frac{1}{2}(log_b3+log_bx)\]