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simplify sqrt 3x^8/sqrt 12x^2
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\[\large \frac{\sqrt{3x+8}}{\sqrt{12x^2}}\]
like that?
saif, shouldn't that "+" sign should be a "^" ?
LOL, right. TYPO.
it is ^8 not +8
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lol, i missed radicals! >.<
@saif i thought you were good with them
\[\frac{\sqrt{3x^8}}{\sqrt{12x^2}}=\frac{x^4\sqrt{3}}{x \sqrt{12}}=\frac{x^3}{\sqrt{4}}=\frac{x^3}{2}\]
\[\Huge \frac{x^3}{2} \]
This site is laging.
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Ajmal's right.
is that the correct answer
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