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can someone check my answer :solve sqrt 2x-3=9 i got x=42
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2x - 3 = 81
yup
Answer to \[\large \sqrt{2x-3}=9\] is x=42, good job
OK - we now have an new expert on radicals !!! well done Jenni.
squaring both sides x=42 ur answer is correct
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\[\sqrt{2x-3}=9\] \[\sqrt{2x-3}^2=9^2\] \[2x-3=81\] + 3 to both sides 2x=84 divide by 2 on both sides x=42
is that right?
yep
perfect.
yay thanks for the help
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