Write the equation of the line with a slope of 3/7 passing through the point (9, -2).
Calculate the equation of the line between the points (-6, -1) and (2, -1).
If MN is the diameter of a circle with M(-3, -4) and N(-7, -14), find the center of the circle.
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OpenStudy (anonymous):
is that a 1 question
OpenStudy (anonymous):
no sir 3 seperate ?
OpenStudy (lalaly):
remainder u wna do it?
OpenStudy (anonymous):
yes
OpenStudy (lalaly):
ok:)
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OpenStudy (anonymous):
laltay can u help me
OpenStudy (lalaly):
laltay? lol ok
OpenStudy (lalaly):
Write the equation of the line with a slope of 3/7 passing through the point (9, -2).
\[y-(-2)=\frac{3}{7}(x-9) \]
\[y=\frac{3}{7}x -\frac{41}{7}\]
Calculate the equation of the line between the points (-6, -1) and (2, -1)
\[slope = \frac{-1-(-1)}{2--6} = 0\]\[y--1=0(x--6) \rightarrow y=-1\]