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Mathematics 13 Online
OpenStudy (anonymous):

y=sinx , then (d^2(cos^7x))/dy^2

OpenStudy (anonymous):

when i asked any question no body reply clearly i don't know why ???

OpenStudy (anonymous):

I just answered one of yours...(Cos^6 one) Maybe u can write as (1-y^2)^3 dy with dy = cosx dx

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