Question

I need help with Adding Radicals

Answer 1

Write the question.

Answer 2

can't really read that. Is that 6x in the 2nd square root? and can't see the 3rd one

Answer 3

this...

\[2\sqrt{24x}+3\sqrt{6x}-2\sqrt{54x}\]?

Answer 4

yes

Answer 5

sorry about that! writing!

Answer 6

\[\sqrt{6x}\] is the answer.

Answer 7

Awww kk thank u!!

Answer 8

\[2\sqrt{24x}+3\sqrt{6x}-2\sqrt{54x}\]

\[=2\sqrt{4\times6 x}+3\sqrt{6x}-2\sqrt{9\times6x}\]

\[=2\times2\sqrt{6 x}+3\sqrt{6x}-2\times3\sqrt{6x}\]

\[=4\sqrt{6 x}+3\sqrt{6x}-6\sqrt{6x}\]
\[=(4+3-6)\sqrt{6 x}=\sqrt{6x}\]

Answer 9

Awww kk thank u!!

Answer 10

AWWWW thank u!!

Answer 11

Awww kk thank u!!

Answer 12

okay i have other one kind of the same

Answer 13

Awww kk thank u!!

Answer 14

Awww kk thank u!!

Answer 15

Awww kk thank u!!

Answer 16

Awww kk thank u!!

Answer 17

is it? 11 root 7?

Answer 18

\[6\sqrt{7}+7\sqrt{7}-2\sqrt{7}=(6+7-2)\sqrt{7}=11\sqrt{7}\]

Answer 19

Awww kk thank u!!

Answer 20

\[6\sqrt{7} +7\sqrt{7} - 2\sqrt{7} would the Anwser be 11\sqrt{7}?\]

Answer 21

if you want text while in math mode use the \text command

then you would get

\[6\sqrt{7} +7\sqrt{7} - 2\sqrt{7}\text{ would the Anwser be }11\sqrt{7}\text{ ?}\]

Answer 22

from my work above you are correct

Answer 23

\[10\sqrt{7} - 15\sqrt{2} + 2\sqrt{3}\]

You can't add or subtract here because the numbers that are in the \[\sqrt{?}\] are all different.