kenny spent one hour more than lucas studying, andrea spent one hour less than twice the hours lucas spent. if together they spent 14 hours, how many more hours did lucas study?
LET lucas = x, kenny = x+1, andrea = 2x-1. Then add them all together, and equate to 14.\[4x = 14\]\[x = 7/2\] or 3 1/2 hours
translate to an equation do not solve
K = L +1 (1), A = 2L -1 (2), K + L + A = 14 (3) From (1) and (3) L+1 = 14 - L - A => A = -2L + 13 (4) From (2) and (4) 2L -1 = -2L + 13 => 4L = 12 => L = 3 i.e A = 5 and K = 4 Kenny spent 4 hours, Andrea spent 5 hours and Lucas spent 3 hours
so i write that whole answer?
my solution is complete and simple, u just need the equations
by the way, analyze the question. I think it's a little tricky. How many MORE hours did Lucas study? hmmm
so i should just type out your answer?
yep
can you look at my other questions too?
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