Question

Solve

sec^2(x)=1

over the interval [(-pi/2), (5pi/2)]

Answer 1

sec = 1/cos

so when does cos(x) = 1 or -1 in the interval?

Answer 2

is y supposed to equal to 1 or x?

Answer 3

\[\sec^2(x)=1\]
\[\sec(x)=1\] or
\[\sec(x)=-1\]
\[\frac{1}{\cos(x)}=1\] or
\[\frac{1}{\cos(x)}=-1\]

Answer 4

which is the same thing as saying
\[\cos(x)=1\] so
\[x=0,x=2\pi\] or
\[\cos(x)=-1\]
\[x=\pi\]