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how do you find the equation of the line given:m=-2;f(1)=2
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y = mx -m(1) + 2
the most common way is to start with a slope definition and work your way to a slope intercept
but the point slope form is just as valid an equation for a line as any other
to which: y-Py = m(x-Px) y - 2 = -2(x-1) in this case
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