Question

Multiply and simplify by factoring:
forth-root(16)*forth-root(128)

Answer 1

\[\sqrt[4]{16}\times \sqrt[4]{128}\] is how it would really look

Answer 2

ok
\[16=2^4\]
\[128=2^7\]so you have
\[\sqrt[4]{2^{11}}\]
4 goes in to 11 twice leaving a remainder of 3, giving
\[2^2\sqrt[4]{2^3}=4\sqrt[4]{8}\]

Answer 3

thank you

Answer 4

yw