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OpenStudy (anonymous):
3x^3 - 4x^2 - 12x + 16 = 0 Solve for 0.
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OpenStudy (anonymous):
come one youngl lady, factor this by grouping: (3x^3-4x^2)-(12x+16), thats a start
OpenStudy (anonymous):
(3x^3-12x)-(4x^2 -16)
OpenStudy (anonymous):
OH THANK YOU, didn't realize I had to move some things around. Thanks :D
OpenStudy (anonymous):
3x(x^2-4) -(4(x^2-4) =(x^2-4)(3x-4)
OpenStudy (anonymous):
awesome, x= -2, 4/3, 2.
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