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(sinxcosx)/(1-2sin^2 x) = (1)/(cotx - tanx) Only work on one side
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nice q .. workin on it
alright
go for the right side of the equation .open it up ... you'll get it easily ..
okay thanks
1/[(cos/sin)-(sin/cos)]--->sin*cos/cos^2-sin^2--->sin*cos/1-2sin^2...got it?
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since cos^2=1-sin^2
Thanks a ton! i really dislike trig
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