Ask your own question, for FREE!
Mathematics 16 Online
OpenStudy (anonymous):

(sinxcosx)/(1-2sin^2 x) = (1)/(cotx - tanx) Only work on one side

OpenStudy (anonymous):

nice q .. workin on it

OpenStudy (anonymous):

alright

OpenStudy (anonymous):

go for the right side of the equation .open it up ... you'll get it easily ..

OpenStudy (anonymous):

okay thanks

OpenStudy (anonymous):

1/[(cos/sin)-(sin/cos)]--->sin*cos/cos^2-sin^2--->sin*cos/1-2sin^2...got it?

OpenStudy (anonymous):

since cos^2=1-sin^2

OpenStudy (anonymous):

Thanks a ton! i really dislike trig

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!