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A simple dartboard has three areas… the main board has a radius of 9 inches, there is a circle with a radius of 6 inches, and the bullseye has a radius of 2 inches. What is the probability of a random dart landing inside the bullseye?
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\[2^{2}/9^{?}\]
Area of inner circle/ area of outermost circle= \[\pi (2^{2})/\pi (9^{2})\]
so then it would be pi * 4 /81 ?
the that would be 0.049 correct ?
answer is 4/81
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=0.049 correct
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