Question

helpp please?

B^2H^5x= T^3K
E^4R Y

Answer 1

question?

Answer 2

its over divison line i need to solve for x please

Answer 3

\[\frac{B^2H^5x}{E^4R}=\frac{T^3K}{Y}\]
?????

Answer 4

if yes
\[B^2H^5x=\frac{T^3K*E^4R}{Y}\]
\[x=\frac{T^3K*E^4R}{Y}-B^2H^5\]

Answer 5

sorry the last step is wrong

answer is\[x=\frac{T^3K*E^4R}{Y*B^2H^5}\]

Answer 6

thanks a lot !!