Question

(1-tanx)/(1+tanx) = (cotx-1)/(cotx-1)

only work on one side

Answer 1

(1-tanx)/(1+tanx) = 1
1 - tanx = 1 + tanx
tan x = 0

Answer 2

typo????

Answer 3

\[LHS=\frac{1-\frac{1}{cotx}}{1+\frac{1}{cotx}}\]
\[\frac{\frac{cotx-1}{cotx}}{\frac{cotx+1}{cotx}}\]
\[\frac{cotx-1}{\cancel{cotx}}*\frac{\cancel{cotx}}{cotx+1}\]
\[\frac{cotx-1}{cotx+1}=RHS\]

Answer 4

No typo

Answer 5

Great! Thanks for your help!