Question

3/4z^3+1/6z^2

Answer 1

\[\frac34z^3+\frac16z^2 = z^2(\frac34z+\frac16)=\frac{z^2}2(\frac32z+\frac13)\]

Answer 2

you need getting the denominator common for 4 and 6 after this check what you will get

Answer 3

because the denominator common is 12 youi will get (9z3 +2z2)/12 = z2(9z+2)/12