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Mathematics 9 Online
OpenStudy (anonymous):

Solve the equation. Express the solution as a radical in the simplest form.

jhonyy9 (jhonyy9):

where is ?

OpenStudy (anonymous):

|dw:1314895631260:dw|

jhonyy9 (jhonyy9):

16(x+3)=x2 x2 -16x -48=0

OpenStudy (anonymous):

do you mean x^2?

OpenStudy (anonymous):

square both sides.

jhonyy9 (jhonyy9):

yes

OpenStudy (anonymous):

oh ok

OpenStudy (anonymous):

Just make sure that whatever solutions you find are valid for the original question.

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

(x-12)(x-4)

OpenStudy (anonymous):

how did you get that ?

OpenStudy (anonymous):

I have no idea, let me try it again

OpenStudy (anonymous):

It's : x^2-16x-48=0 not: x^2-16x+48=0

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

I got tht

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