Question

a rectangle has an area of 60 square inches and a perimeter of 38 inches. what is the length and width of the rectangle?

Answer 1

l*w = 60
2l + 2w = 38

solve for l and w

Answer 2

l*w=60----1
2(l+w)=38
l+w=38/2
l+w=19
l=19-w-----2

substitute 2 in 1

(19-w)(w)=60
19w-w^2=60
w^2-19w+60=0
w^2-15w-4w+60=0
w(w-15)-4(w-15)=0
(w-15)(w-4)=0
w=15,w=4

so length=15 and width=4