Question

Solve the equation √x^2 + 5 = 3-x

Answer 1

square both sides to get
\[x^2+5=(3-x)^2=x^2-6x+9\] then solve
\[x^2+5=x^2-6x+9\]
\[5=-6x+9\]
\[-6x=-4\]
\[x=\frac{2}{3}\]and check the answer