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Multiply (a+g)(a^2-ag+g^2)
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\[a^3+g^3\]
if you recognize it as the formula for factoring the sum of two cubes. otherwise you have to do 6 multiplications and a raft of cancellation
(a+g)(a^2-ag+g^2) =a(a^2-ag+g^2)+g(a^2-ag+g^2) =a^3-a^2g+ag^2+a^2g-ag^2+g^3 =(a^3+g^3)
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