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Factor. If polynomial is prime then state this. q^2+1
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(q+1)(q-1)
\[\Huge (q+1)(q-1)\]
Mine's look cool & BIG.
LOL, who cares its the same answer anyways You plagiarized mine arghh Its a sin to plagiarise :P:PPjks
you guy put the difference of 2 squares, but the question asked is a sum of 2 squares. Over real numbers this is prime. Over complex numbers its:\[(x+iy)(x-iy)\]
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Oh woops , sorry I didn't understand the question .
Thanks Joe!
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