can someone help me with the square roots i dont understand them!
i can help
? wht's ur q?
thank u !
qus?
is2aleeee
???????????????????????
like if u have a number that .. like 899 how do u do it ???!!
\[\sqrt{899}\]
?????
what i cannt understand
how can u solve this \[\sqrt{899}\]
ok
what is the basic thing or the first thing u think of to do it ??
prime factors
well normally u should express it as sqr(x*y) whr x is a perfect sqr but i can't find a solution abt this one.... but 4 example if u have sqr(162)=sqr(81*2)=9sqr2
ohh then u see what times what gives u this no. or am i wrong?
a_clan what do u mean by prime factors?
prime factors for 12, =2*2*3
so.. i didnt understan where do u put them ? the no.s
examples...
in case of 899 which I think is a prime number, the only way to do is by the standard procedure for square root
what is standard procedure
\[\sqrt{12} = \sqrt{2*2*3}=2\sqrt{3}\]
isma3i, hl2 awl ma tshufee hek root btehke esh el prime factors (el arqam el awaleye tb3to) hon 29 w 31, b3den btehke hadol fehom she elo jather, fa l2, so hada el squareroot ma elo simplifying, fa ya emma btktobeeh raqm 3ade, aw bthotteeh zy ma hwe masalan sqrt 8 8=2*2*2 = 4*2 4 ilo squareroot, elle hwe 2 fa btktobe squareroot of 8 2 sqrt 2
\[\sqrt{899}=\sqrt{29 \cdot 31}=\sqrt{899}\] there are perfect squares inside so we can not simplify anymore
ohh tabb in a_clan's example how did he do it ino lais tala3 il 2 aw 7at il 2 bara ?
3shan 12 = 4*3 w sqrt 4 =2 w el 3 ma elha sqrt, fa 2 sqrt3
ohh hala2 fhimit but can u give me last example 3ashan tod5ol bi3a2li tamaman
and by the way thank you
there are no* lol i didn't realize i missed that word
ok masalan sqrt 125 125 = 5*5*5 = 25*5 hl2 25 elha sqrt elle hwe 5 sah? so sqrt 125 = sqrt25*5 = sqrt25*sqrt5 = 5 sqrt5
ya3ni haiik \[25\sqrt{5}\]
i mean \[5\sqrt{5}\]
|dw:1314960631853:dw|
Join our real-time social learning platform and learn together with your friends!