Question

(ax/cos theta)+(by/sin theta)=a^2-b^2 and (axsin theta/cos^2 theta)-(bycos theta/sin^2 theta)=0
show that (ax)^2/3 +(by)^2/3=(a^2-b^2)^2/3

Answer 1

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Answer 2

It may not what you want but a Mathematica solution with comments is attached.