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Find the general solution of the homogeneous differential equation (x^2-y^2)dx+(3xy)dy=0
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\[y=\pm \sqrt{2c1x ^{2/3}-x ^{2}}/\sqrt{2}\]
could i write that as: (x^2+2y^2)^3=cx^2
??
this is not a exact equation
sorry, should have been y(x)=
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I think u sub y= vx, it can be made manageable.
U will get a separable equation.
->(x^2-vx^2)dx +3vx^2 dy (and dy= vdx+xdv) then rearrange.
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