helppppp differentiate tan^7(4x^2+9x+2)
easy question
mimi solve it
\[\huge \begin{array}l\color{red}{\text{¿}}\color{orange}{\text{u}}\color{#9c9a2e}{\text{ʍ}}\color{green}{\text{o}}\color{blue}{\text{p}}\color{purple}{\text{ }}\color{purple}{\text{ǝ}}\color{red}{\text{p}}\color{orange}{\text{ı}}\color{#9c9a2e}{\text{s}}\color{green}{\text{d}}\color{blue}{\text{n}}\color{purple}{\text{ }}\color{purple}{\text{p}}\color{red}{\text{ǝ}}\color{orange}{\text{l}}\color{#9c9a2e}{\text{l}}\color{green}{\text{ɐ}}\color{blue}{\text{ɔ}}\color{purple}{\text{ }}\color{purple}{\text{ǝ}}\color{red}{\text{u}}\color{orange}{\text{o}}\color{#9c9a2e}{\text{ǝ}}\color{green}{\text{ɯ}}\color{blue}{\text{o}}\color{purple}{\text{s}}\color{purple}{\text{ }}\color{red}{\text{p}}\color{orange}{\text{ı}}\color{#9c9a2e}{\text{p}}\color{green}{\text{}}\end{array}\]
Easy ??! wth , i dont even know how to differentiate tan xD so~ embaressing xD
me too....im still in pre-school...=)
let me show u 7tan^6(4x^2+9x+2)*sec^2x(4x^2+9x+2)*(8x+9)
easy question
\[\huge\begin{array}l\color{#FF0000}{\text{ฬ}}\color{#FF7F00}{\text{ђ}}\color{#FFE600}{\text{ค}}\color{#00FF00}{\text{t}}\color{#0000FF}{\text{ }}\color{#6600FF}{\text{ค}}\color{#8B00FF}{\text{๒}}\color{#FF0000}{\text{๏}}\color{#FF7F00}{\text{ย}}\color{#FFE600}{\text{t}}\color{#00FF00}{\text{ }}\color{#0000FF}{\text{t}}\color{#6600FF}{\text{ђ}}\color{#8B00FF}{\text{เ}}\color{#FF0000}{\text{ร}}\color{#FF7F00}{\text{ }}\color{#FFE600}{\text{ร}}\color{#00FF00}{\text{t}}\color{#0000FF}{\text{ץ}}\color{#6600FF}{\text{l}}\color{#8B00FF}{\text{є}}\color{#FF0000}{\text{؟}}\end{array}\]
lolss ok xD
\[\huge\begin{array}l\color{#FF0000}{\text{u}}\color{#FF7F00}{\text{ʍ}}\color{#FFE600}{\text{ö}}\color{#00FF00}{\text{p}}\color{#0000FF}{\text{ }}\color{#6600FF}{\text{ë}}\color{#8B00FF}{\text{p}}\color{#FF0000}{\text{ï}}\color{#FF7F00}{\text{s}}\color{#FFE600}{\text{d}}\color{#00FF00}{\text{ü}}\color{#0000FF}{\text{ }}\color{#6600FF}{\text{ë}}\color{#8B00FF}{\text{1}}\color{#FF0000}{\text{ÿ}}\color{#FF7F00}{\text{ʇ}}\color{#FFE600}{\text{s}}\color{#00FF00}{\text{ }}\color{#0000FF}{\text{ë}}\color{#6600FF}{\text{ɯ}}\color{#8B00FF}{\text{ä}}\color{#FF0000}{\text{s}}\color{#FF7F00}{\text{ }}\color{#FFE600}{\text{ë}}\color{#00FF00}{\text{ɥ}}\color{#0000FF}{\text{ʇ}}\color{#6600FF}{\text{ }}\color{#8B00FF}{\text{ʇ}}\color{#FF0000}{\text{ü}}\color{#FF7F00}{\text{ö}}\color{#FFE600}{\text{q}}\color{#00FF00}{\text{ä}}\color{#0000FF}{\text{ }}\color{#6600FF}{\text{ʍ}}\color{#8B00FF}{\text{ö}}\color{#FF0000}{\text{ɥ}}\end{array}\]
\[\Huge \begin{array}l\color{red}{\text{ї}}\color{orange}{\text{ }}\color{#9c9a2e}{\text{Ć}}\color{green}{\text{α}}\color{blue}{\text{η}}\color{purple}{\text{ }}\color{purple}{\text{®}}\color{red}{\text{З}}\color{orange}{\text{α}}\color{#9c9a2e}{\text{Ð}}\color{green}{\text{ }}\color{blue}{\text{α}}\color{purple}{\text{ь}}\color{purple}{\text{☺}}\color{red}{\text{ϋ}}\color{orange}{\text{†}}\color{#9c9a2e}{\text{ }}\color{green}{\text{§}}\color{blue}{\text{†}}\color{purple}{\text{ү}}\color{purple}{\text{₤}}\color{red}{\text{З}}\color{orange}{\text{§}}\color{#9c9a2e}{\text{!}}\color{green}{\text{}}\end{array}\]
Hashir , is that the answer to it ? xD
is that correct???
\[\tan^7(4x^2+9x+2)=[\tan(4x^2+9x+2)]^7\] \[\frac{d}{dx}([\tan(4x^2+9x+2)]^7=7[\tan(4x^2+9x+2)]^6\sec^2(4x^2+9x+2)(8x+9)\]
yes it indeed is
you have little mistake above
yes typo !!!
its sec^2 on sec^2x
hehhehehhehe....ok...typo error...i wont let you integrate your answer..
Oh cool~ i just learnt something new today xDD
we used something called the chain rule and the power rule
and the constant rule
derivative terms
simplest theory is differentiate the outer function first then the ineer on until u are on the simplest function
LOL, i know I just don't know how to differentiate tan xD
i think most outer to very inner is easier i think some people like inner to outer
yes it upto them
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