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Solve the inequality. x^(3)+5x^(2)≥4x+20 Write your answer as an interval or union of intervals.
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its a grouping factor
maybe x^(3)+5x^(2)≥4x+20
x^3 +5x^2 -4x +20 ≥ 0 (x^3 +5x^2) + (-4x +20) ≥ 0 x^2(x +5) + -4(x-5) ≥ 0 ; almost :)
doh!! ... i typoed the 20 when i brought it over .... mathing and typing do not mix
x^3 +5x^2 -4x -20 ≥ 0 (x^3 +5x^2) + (-4x -20) ≥ 0 x^2(x +5) -4(x+5) ≥ 0 (x^2-4)(x +5) ≥ 0 ; (x^2-4) is a diff of squares (x+2)(x-2)(x+5) ≥ 0
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lol...my solution is x>2.....I'm lost I guess
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