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2x + 9√(x) - 5 = 0 ; need help solving for x
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its a quadratic; disguised
[√(x)]^2 = x
would i have to sqare everything else too?
no, its just the "form" that you are interested in; the structure of the variable is unimportant at the moment; solve it for: √(x) = quadratic formula outputs
then determine x from that
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alright thanks
if its right in me head i see it as: 2(5) = 10 10-1 = 9 (√(x)+10/2)(√(x)-1/2) (√(x)+5)(√(x)-1/2) √(x) = -5 or 1/2 [√(x) = -5 or 1/2] ^2 x = 25 or 1/4
the 25 might be a bad result that comes with the territory :)
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