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OpenStudy (anonymous):
a simple pendulum is 50cm long its frequency of vibration on the surface of the earth is 1hz 0.5hz 0.7 0.65
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OpenStudy (anonymous):
0.7 is answer....
OpenStudy (anonymous):
T=2*pi*squareroot(length/g) , T=2*3.14159*squareroot(50*10^-2/9.8)= 1.42s , f=1/T=1/1.42=0.7Hz
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