What is the domain and range of the quadratic equation y = –x^2 – 14x – 52?

Question

anonymous · Answer

domain is all real numbers (as for any poly function)

anonymous · Answer

Putting it into vertex form
-(x^2+14x) - 52
-(x^2 + 14x + 49) - 52 + 49
-(x+7)^2 - 3
So y ≤ -3

anonymous · Answer

The range is in in$$(-\infty,-3]$$terval notation

anonymous · Answer

this has a maxm value at vertex - the graph is open downwards

vertex is at (-7,-3)
domain is all real numbers
range is f(x) < = -3

anonymous · Answer

Vertex has coordinates x--b/2a $$x=-14/2(-1)=-7$$Vertex has y-coordinate y=f(-b/2a) $$y=-(-7)^2-14(-7)-52=-3$$ Since th parabola opens downward, the vertex is max