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Can this be factored completely? (x-3)^2(2x+1)^3+(x-3)^3(2x+1)^2
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both terms both have (x-3)^2 in common both terms both have (2x+1)^2 in common so we can factor that out (x-3)^2(2x+1)^2[(2x+1)+(x-3)] (x-3)^2(2x+1)^2(3x-2)
Is 2x+2 correct or is it 3x+2? I'm going to do it again
its 3x-2
I'm wrong. I wrote it down incorrectly.
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