Question

Help! solve this equation for x
(2/(x+5)+(1/(x-5)=(16/(x^2-25)

Answer 1

\[\frac{2}{x+5}+\frac{1}{x-5}=\frac{16}{x^2-25}\]
\[\frac{2(x-5)+1(x+5)}{x^2-25}=\frac{16}{x^2-25}\]
\[2x-10+x+5=\frac{16}{\cancel{(x^2-25)}}*\cancel{(x^2-25)}\]
\[3x-5=16\]
\[3x=16+5\]
\[x=\frac{21}{3}=7\]