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Mathematics 7 Online
OpenStudy (anonymous):

^3√72*t^8

OpenStudy (anonymous):

I came up with 2t^2^3√9t^2

jimthompson5910 (jim_thompson5910):

\[\large \sqrt[3]{72t^8}\] \[\large \sqrt[3]{8\times 9t^6\times t^2}\] \[\large \sqrt[3]{8}\times\sqrt[3]{ 9}\times\sqrt[3]{t^6}\times \sqrt[3]{t^2}\] \[\large 2\times\sqrt[3]{ 9}\times t^2\times \sqrt[3]{t^2}\] \[\large 2t^2\sqrt[3]{ 9t^2}\] So \[\large \sqrt[3]{72t^8}=2t^2\sqrt[3]{ 9t^2}\]

jimthompson5910 (jim_thompson5910):

I'm assuming that 3 in your answer is the index. If so, then you have the right answer.

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