Question

complete the square -3x^2-12x-11

Answer 1

-3x^2-12x-11

-3(x^2+4x+4)+1

Do you need help on how this answer was obtained?

Answer 2

\[\large -3x^2-12x-11\]


\[\large -3\left(x^2+4x+\frac{11}{3}\right)\]


\[\large -3\left(x^2+4x+4-4+\frac{11}{3}\right)\]


\[\large -3\left((x+2)^2-4+\frac{11}{3}\right)\]


\[\large -3\left((x+2)^2+\frac{1}{3}\right)\]


\[\large -3(x+2)^2-3\left(\frac{1}{3}\right)\]


\[\large -3(x+2)^2-1\]
So \[\large -3x^2-12x-11=-3(x+2)^2-1\]

Answer 3

thanks

Answer 4

Yeah - factorise the middle bit you get:
-3(x+2)^2 -1
My bad.