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Mathematics 8 Online
OpenStudy (anonymous):

1-log(b)14=

OpenStudy (anonymous):

does this say \[1-\log_b(14)=?\]

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok then we get \[\log_b(14)=1\] so \[b^1=14\] makingn \[b=14\]

OpenStudy (anonymous):

wow, so simply put.

OpenStudy (anonymous):

1 down, two to go

OpenStudy (phi):

@sat. is this an equation? I don't see = 0

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