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Mathematics 13 Online
OpenStudy (anonymous):

In 1994 ,the life expectancy of males in a certain country was 65.5 years in 2001 ,it was 68.2 years let E represent the life expectancy in year T and let T represent the number of year since 1994

OpenStudy (anonymous):

The liner E (t) that fits the date is (round to the nearest tenth )

OpenStudy (anonymous):

use the function to predict life expectancy of males in 2009 E (15) round to the nearest tenth

OpenStudy (anonymous):

this is the same as "find the equation of the line between the points (0,65.5) and (7,68.2)

OpenStudy (anonymous):

since we are starting at 1994 we can make that year 0 slope is \[m=\frac{68.2-65.5}{7}=.3857\] rounded. so we assume increase per year of \[.3857\] years

OpenStudy (anonymous):

so your formula would be \[E=.3857T+65.5\]

OpenStudy (anonymous):

nearest tenth is \[E=0.4T+65.5\]

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