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In 1994 ,the life expectancy of males in a certain country was 65.5 years in 2001 ,it was 68.2 years let E represent the life expectancy in year T and let T represent the number of year since 1994
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The liner E (t) that fits the date is (round to the nearest tenth )
use the function to predict life expectancy of males in 2009 E (15) round to the nearest tenth
this is the same as "find the equation of the line between the points (0,65.5) and (7,68.2)
since we are starting at 1994 we can make that year 0 slope is \[m=\frac{68.2-65.5}{7}=.3857\] rounded. so we assume increase per year of \[.3857\] years
so your formula would be \[E=.3857T+65.5\]
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nearest tenth is \[E=0.4T+65.5\]
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