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Mathematics 7 Online
OpenStudy (anonymous):

25b^2+35b-30 factor

OpenStudy (anonymous):

(5b-3)(5b+10)

OpenStudy (anonymous):

suppose to be 5(b+2)(5b-3) im just leaning how to do these i cannot catch on for the life of me

OpenStudy (anonymous):

(5b-3)(5b+10) = 5(5b-3)(b+2)

OpenStudy (anonymous):

practice on how to factor a three terms-2nd degree experession

OpenStudy (anonymous):

you start by factoring out the 5 and that leaves 5b^2+7b-6 from there it is just a matter of factoring the quadratic, which is sort of a pain if you're not used to it. There's no quick answer but this might help http://www.purplemath.com/modules/factquad2.htm

OpenStudy (anonymous):

ty

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