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Can someone explain to me how to factor this: y(3y+11)=20
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\[3y^2 +11y-20 =0\]\[(y+5)(3y-4) =0\]
muliply : 3y^2+11y -20 =0 ===> (3y -4 ) (y+5) = 0 ===> y=4/3 or y=-5
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