Question

find the solution set:
\[9x^{4}-145x^{2}+16=0\]

Answer 1

\[\pm4,\pm\frac{1}{3}\]

Answer 2

how did you get that? :)

Answer 3

let \[u=x^2\] then you can use the quadratic formula

Answer 4

Zarkon your answer is wrong. read the question carefully

Answer 5

oh sorry i placed the wrong equation
9x^{-4}-145x^{-2}+16=0

Answer 6

\[9x^{-4}-145x^{-2}-16=0\]

Answer 7

thank you thank you so much :)