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Mathematics 13 Online
OpenStudy (anonymous):

solve |x-1/2|>3

OpenStudy (zarkon):

as written the solution is \[x<\frac{-5}{2}\text{ or }x>\frac{7}{2}\]

OpenStudy (anonymous):

it use [] to represent the absolute value for convenience. [x-0.5]>3 so in this case, x-0.5 must be numerically greater than 3. (numerically means regardless of its sign) x-0.5 must be greater than 3 or lower than -3 in order to achieve this. x>3.5 or x<-2.5

OpenStudy (anonymous):

Solution is: Re(x)>7/2 and Re(x)<-5/2

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