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OpenStudy (anonymous):
(3(x-7))/(x+2)(2x-1) times (4x^2+6x-4)/(4x-28)
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OpenStudy (anonymous):
can you factor the numerator of the second fraction?
OpenStudy (anonymous):
and also factor the denominator of that second fraction, once you do that the answer will become clear to you
OpenStudy (anonymous):
ok thanks
OpenStudy (anonymous):
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