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The longest side of a triangle is two times the shortest side. The medium side is 3 meters more than the shortest side. Perimeter is 27 meters. Find the dimensions
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let the longest side=x medium side=y shortest side=z x=2z y=z+3 x+y+z=27 now solve
Let x, y and z be the longest, medium and shortest sides respectively: x = 2z y = z+3 z = z x+y+z = 27, so (2z)+(z+3)+(z) = 27, 4z+3 = 27, z = 8 The rest should follow.
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