A tourist being chased by an angry bear is running in a straight line toward his car at a speed of 4.2 m/s. The car is a distance d away. The bear is 30 m behind the tourist and running at 6.0 m/s. The tourist reaches the car safely. What is the maximum possible value for d?

Question

anonymous · Answer

the maximum possible value for d occurs when tourist and the bear reach the car at the same time .
now distance=velocity *time
let the tourist cover the distance in a time t 
then d= 4.2*t
now the bear also takes the same time to reach the car
the d+30=6*t
d/4.2 = (d+30)/6
then solve for d 
you will get d = 70m