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ax/cos theta)+(by/sin theta)=a^2-b^2 and (axsin theta/cos^2 theta)-(bycos theta/sin^2 theta)=0 show that (ax)^2/3 +(by)^2/3=(a^2-b^2)^2/3
It will take time ....Looks complicated
i got its answer bt its too lengthy i feel there is an easier way out
plz help
Hey I solved this already... :(
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