Question

A person walks 20.0° north of east for 3.11 km. How far would she have to walk due north and due east to arrive at the same location?
?=km (due north)
?=km (due east)

Answer 1

You have a right triangle with a hypotenuse of 3.11 km and and angle (marked by theta) of 20 degrees. Use trigonometry. Y component (North) is given by\[3.11\times \sin20\]X component (South) is given by\[3.11\times \cos20\]

Answer 2

Edit: x component (East)

Answer 3

Thank You!