Question

what is the inverse of log (base of 2) (x+1)?

Answer 1

the inverse of log is exponent

Answer 2

x+1 = 2^y

Answer 3

maybe go a little further :)

Answer 4

\[y=\log_2(x+1) => 2^y=2^{\log_2(x+1)}=>2^y=x+1=> x=2^y-1\]