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5x^3 + x^2 - 20x - 4
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factorize or solve = 0?
factor
ok, with x^3 u usually have to guess one of the solutions and then make polinomial division
but thre might be another way for this one let me check 1 sec
|dw:1315344508816:dw|
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(x-2)(5x^2+11x+2)
(x-2)(5x^2+11x+2)
(x-2) (x+2) (5 x+1)
yes, is a double fact first asociate 5x³+x² and - (20x-4) so x²(5x+1)-4(5x+1)
\[5x^3+x^2-20x-4=(5x^3+x^2)+(-20x-4) \] \[=x^2(5x+1)-4(5x+1)=(5x+1)(x^2-4)=(5x+1)(x-2)(x+2)\]
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