Question

not sure if im doing this right for Lim ln(x-1)^2/ ln(x-1) as x->2

Answer 1

use logarithm properties to get the ^2 out
so it is
\[(2\times \ln (x-1))\div \ln (x-1)\]

Answer 2

simplifies to 2

Answer 3

Are you serious. here i was doing all sorts of crazy things.. when in reality this was a one step problem... UGHHHH