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3/(x-2)+ 1/2=x/x-2
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\[ \frac{3}{x-2}+\frac{1}{2}=\frac{x}{x-2}\] \[\frac{3(2)+1(x-2)}{2(x-2)}=\frac{x}{x-2}\] \[6+x-2=\frac{x(2)\cancel{(x-2)}}{\cancel{(x-2)}}\] \[4+x=2x\] \[x=4\]
thanks i really appriecate your help...i see where im going wrong.
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