Question

question on writing equations:
The perimeter of a rectangle is 482 cm. The length is 6 cm greater than 4 times the width. Find the length.

Answer 1

The perimeter of a rectangle is 482 cm
2*L+2*w = 482
The length is 6 cm greater than 4 times the width.
L=4*w+6
Find the length.
Solve the following equations for L and w:
{2*L+2*w = 482, L=4*w+6}
{L -> 194, w -> 47}

Answer 2

Length = 2(4w +6)
Width = 2w

Set the equation up.
2w + 2(4w +6) = 482

Find the w (width)
2w + 2(4w +6) = 482
2w + 8w + 12 = 482
10w + 12 = 482
10w = 482-12
10w = 470
\[\frac{10w}{10} = \frac{470}{10} \]
w (width) = 47

Now that we have the width we look at where says that the Length is 6 cm Greater than 4 times the width

So we use the 47, which is our width. So we are looking for 4w +6 plug the 47 into the w because 47 is our width

4(47) + 6 = 194
So our length is 194